-0.06x^2+1.02x=0

Solution for -0.06x^2+1.02x=0 equation:

-0.06x^2+1.02x=0

a = -0.06; b = 1.02; c = 0;
Δ = b2-4ac
Δ = 1.022-4·(-0.06)·0
Δ = 1.0404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.02)-\sqrt{1.0404}}{2*-0.06}=\frac{-1.02-\sqrt{1.0404}}{-0.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.02)+\sqrt{1.0404}}{2*-0.06}=\frac{-1.02+\sqrt{1.0404}}{-0.12}
$